Question

Find an equation for the nth term of the arithmetic sequence.

a14 = -33, a15 = 9

an = -579 + 42(n + 1)
an = -579 + 42(n - 1)
an = -579 - 42(n + 1)
an = -579 - 42(n - 1)

Answer 1

Just plug in the value n=14 and n=15 in to all of those equations, and the if you get -33 and 9 respectively, that is the answer that is correct.

Do you need help with how to generate an arithmatic sequence based upon two consecutive terms?

Answer 2

i need help with this whole lesson to be honest.. ive been really struggling

Answer 3

nth term = a1 + (n - 1)d

where a1 = first term, and d = common difference

in this case the value of d = 9 - (-33)

Answer 4

you can find what the first term is by substituting in the formula an = a1 +(n-1)d

Answer 5

what is the value of d
9 -(-33) = 42 right?

Answer 6

yes

Answer 7

15th term = 9
so substituting

9 = a1 + (15 - 1)42

Answer 8

from this we can find the first term a1

Answer 9

a1 = 9 - 14*42 = -579

Answer 10

get it or have i gone too fast?

Answer 11

okay that sounds easy.....

Answer 12

yes you just plug in the values for a1 and d into an = a1 + d(n - 1)

Answer 13

Arithmetic sequences are of the form
a1 , a1+d, a1 + 2d, a1 + 3d .......

each value after the first is obtained by adding the common difference d

Answer 14

a simple one would be
3 , 6, 9, 12 ....

Answer 15

im so sorry.. its really just not clicking together right now.. okay so for that example you just gave ... 3= a1 correct? then a1+d= 6? and so on .. right??

Answer 16

yes second term is 3 +3 = 6

Answer 17

then 3 + 2(3) = 9

Answer 18

glad to be of help but i just got to go right now

Answer 19

thanks for the help ! :)

Answer 20

SO the answer would be B
an = -579 + 42(n - 1)