Question

please help

Answer 1

Using the ratio of perfect squares method, what is \[\sqrt{41}\] rounded to the nearest hundredth?

Answer 2

@welshfella

Answer 3

@iGreen

Answer 4

@rational

Answer 5

@sammixboo

Answer 6

any one

Answer 7

is it 6.4?

Answer 8

I'm afraid I've never heard of that . I'll have to look it up. Sorry, cant help

Answer 9

do you know anyone that could help?

Answer 10

@dan815

Answer 11

@Hero

Answer 12

@SolomonZelman

Answer 13

@AlexandervonHumboldt2

Answer 14

im sure someone here will help I'm a bit puzzled though. Because 41 is a prime number so you cant factor it.

Answer 15

i know but there is a way to do it

Answer 16

the answer will be somewhere between 6 and 7 as 6^2 = 36 and 7^2 = 49
6.5^2 = 42.5

Answer 17

* 42.25

Answer 18

@texaschic101

Answer 19

@TheSmartOne

Answer 20

whats the point of this website if no one helps or someone takes a hour to do it

Answer 21

hold on - this might be the way to do it
we know it lies betwwen 6 and 7
and ratio of the squares is 36/49
now 41 - 36 = 5

so maybe its 36 + 5 * (36/49)

Answer 22

no thtat last bit is wrong of couse
its 6 + 5*(36/49)

Answer 23

no sorry that wont give the right answer

Answer 24

its not logical anyway

Answer 25

the correct answer is 6.38

Answer 26

http://prntscr.com/6tv2fq