Question

Please help?

Find the standard form of the equation of the parabola with a focus at (7, 0) and a directrix at x = -7.

y = (1/28)x2
x = (1/28)y2
-28y = x2
y2 = 14x

Answer 1

here is a diagram showing the information you have been given



the vertex is a units below the focus and the position is

(7 - a, 0)

the since the parabola is concave right the general form is

\[(y-k)^2 = 4a(x - h)\]

where the vertex is (h, k) and a is the focal length.

hope it helps