Question

sqrt 9 m^2 n^2 + 2 sqrt m^2 n^2 - 3mn

sqrt mn
2mn

Answer 1

@Godlovesme

Answer 2

@inowalst

Answer 3

please draw parenthesis to indicate where square roots start and stop.

Answer 4

Agreed, it currently reads \[\sqrt {9 m^2 n^2 + 2 \sqrt {m^2 n^2 - 3mn}
}\]

Answer 5

if you add a \ {bracket} to the beginning and the end you can type it as you did.

Answer 6

\(\normalsize\color{royalblue}{ \rm \sqrt{9 m^2 n^2} + 2\sqrt{m^2 n^2} - 3mn }\)

Answer 7

correct?

Answer 8

first, \(\normalsize\color{royalblue}{ \rm \sqrt{9 m^2 n^2} + 2\sqrt{m^2 n^2} - 3mn }\)

can be re-written as
\(\normalsize\color{royalblue}{ \rm \sqrt{3^3 m^2 n^2} + 2\sqrt{m^2 n^2} - 3mn }\)
\(\normalsize\color{royalblue}{ \rm \Downarrow }\)
\(\normalsize\color{royalblue}{ \rm \sqrt{(3mn)^2} + 2\sqrt{m^2 n^2} - 3mn }\)

(will assume positive m and n, to avoid the absolute value)
\(\normalsize\color{royalblue}{ \rm \Downarrow }\)
\(\normalsize\color{royalblue}{ \rm 3mn + 2\sqrt{m^2 n^2} - 3mn }\)

Answer 9

what cancels out so far?
(Hint: \(\normalsize\color{royalblue}{ \rm \color{red}{3mn }+ 2\sqrt{m^2 n^2} \color{red}{- 3mn} }\) )

Answer 10

so its 2mn?

Answer 11

you may or may not be correct, first tell us how you came to that conclusion.

Answer 12

After you subtracted the 3mn 's , you remained with
\(\normalsize\color{royalblue}{ \rm 2\sqrt{m^2n^2} }\)

Answer 13

We are not saying you are right, or you are wrong, we just want to see your thinking that made you conclude to the answer
(because, we hope you aren't just guessing from the answer choices)

Answer 14

thanks