Which logarithmic graph can be used to approximate the value of y in the equation 2y = 5?
did you type that correctly? There is not need for logs in that eq
yes i did heres the graphs
well, solve your eq for y to begin
how do i do that?
you don't know how to solve 2y=5 for y?
its 2^y=5
that makes more sense now
alright, so, in order to get y out of the exponent, we need to undo it. The opposite of the exponent function is the log function. now, there are different bases for logs, you can have log base anything. Here we can use log base 2 to undo, 2^y
just remember we need to do this to both sides
so 2*^2 ?
not, quite. We write it like this \[log_2(2^y)=log_2(5)\]
so now, we know that the log base 2 undo's the 2^y, so we are just left with y. and we get \[y=log_2(5)\] so now, you just plug it into your calculator and see which point marked is closer.
but again, I think there is a type-o because none of those are a horizontal line.
thats excatly how i copied it from the problem
could it be the last graph? @FibonacciChick666
well, what is log base 2 of 5? (you can use wolfram alpha to figure that out if you wish)
just a couple of decimal places, not all of em
it was the last graph
I know that is the only option(even though this is a very poorly phrased question), I just wanted to make sure you could figure out that value.
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