a country's population in 1994 was 140 million. In 1998 it was 146 million. Estimate the population in 2011 using the exponential growth formula. Round your answer to the nearest million.
P=Ae^kt

Question

a country's population in 1994 was 140 million. In 1998 it was 146 million. Estimate the population in 2011 using the exponential growth formula. Round your answer to the nearest million. 
P=Ae^kt

anonymous · Answer

0.7!!!!!!!!!!!! THERE!

anonymous · Answer

what does 0.7 represent?

wolf1728 · Answer

42 cookiethere isn't here anymore
I'll get an answer for you.

anonymous · Answer

does .07 represent k?

wolf1728 · Answer

I do not know what k represents 
Maybe 42cookie just typed anything
I'll work on the answer

campbell_st · Answer

1st task is to find k

so 

$$146 = 140 \times e^{4k}$$

solve for k

anonymous · Answer

2.269?

campbell_st · Answer

no... 

divide both sides by 140$$\frac{146}{140} = e^{4k}$$

then take the ln of both sides and divide the answer by 4

that will give you a value for the growth constant k... 

then use that with P = 140 and t = 17 to find the population in 2011

anonymous · Answer

I'm gettinf 0.167

anonymous · Answer

getting*

wolf1728 · Answer

ln means natural log

ln (146/140) = ln (e^4*k) 

 0.04196419914 = 4*k

anonymous · Answer

Couldn't figure it out but thanks!

wolf1728 · Answer

k = 0.0104910498

wolf1728 · Answer

Population 1998 = 140 mil * e^(0.0104910498 * 4)

Population 1998 = 140 * 1.0428571429

Population 1998 = 146 million

wolf1728 · Answer

Population 2011 = 140 mil * e^(0.0104910498 * 17)

Population 2011 = 140 mil * e^(0.1783478466)

Population 2011 = 140 mil * 1.1952410094

Population 2011 = 167,333,741

Yes, it's just that easy!!!  LOL