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Mathematics 18 Online
OpenStudy (anonymous):

Plz help Wendy throws a dart at this square-shaped target: Part A: Is the probability of hitting the black circle inside the target closer to 0 or 1? Explain your answer. (5 points) Part B: Is the probability of hitting the white portion of the target closer to 0 or 1? Explain your answer. (5 points)

OpenStudy (anonymous):

OpenStudy (anonymous):

what do you think?

OpenStudy (anonymous):

ummm for part a 0?

OpenStudy (anonymous):

true and the opposite for part b

OpenStudy (anonymous):

ok

OpenStudy (michele_laino):

here we have to compute the area of the black circle

OpenStudy (michele_laino):

furthermore, we have to compute the area of the white square

OpenStudy (anonymous):

ok

OpenStudy (michele_laino):

what is the area of the white square?

OpenStudy (anonymous):

100

OpenStudy (michele_laino):

ok!

OpenStudy (michele_laino):

what is the area of the black circle? hint: you can use this value \[\pi = 3.14\]

OpenStudy (anonymous):

I don't know what the radius is

OpenStudy (michele_laino):

the radius is half-diamter, so: radius = 2/2=...?

OpenStudy (anonymous):

1

OpenStudy (michele_laino):

ok!

OpenStudy (michele_laino):

so what is the area of the circle?

OpenStudy (anonymous):

it's 3.14

OpenStudy (michele_laino):

hint: \[area = \pi \times {\left( {radius} \right)^2}\]

OpenStudy (michele_laino):

ok!

OpenStudy (michele_laino):

now, the requested probability in part A, is given by the subsequent ratio: \[\large p = \frac{{area\;of\;the\;circle}}{{area\;of\;the\;square}} = ...?\]

OpenStudy (michele_laino):

since the favorable cases are given by the area of the black circle, whereas the possible cases are given by the area of the white square

OpenStudy (anonymous):

0.0314

OpenStudy (michele_laino):

ok! We can write that probability in percentage form, so we have: p= 3.14 %

OpenStudy (anonymous):

ok

OpenStudy (michele_laino):

Now, what is the difference between the area of the square and the area of the circle? Namely what is: 100-3.14=...?

OpenStudy (anonymous):

96.86

OpenStudy (michele_laino):

ok! For the part A, we can say that the probability is closer to 0, since 0.0314 is closer to zero

OpenStudy (anonymous):

ok

OpenStudy (michele_laino):

Finally, the requested probability in part B, is given by the subsequent formula: \[p = \frac{{area\;of\;the\;square - area\;of\;the\;circle}}{{area\;of\;the\;square}} = ...?\]

OpenStudy (michele_laino):

since, the favorable cases are given by the difference between those areas, whereas the possible cases are given by the area of the square

OpenStudy (michele_laino):

\[\Large \begin{gathered} p = \frac{{area\;of\;the\;square - area\;of\;the\;circle}}{{area\;of\;the\;square}} = \hfill \\ \\ = \frac{{96.86}}{{100}} = ...? \hfill \\ \end{gathered} \]

OpenStudy (anonymous):

0.9686

OpenStudy (michele_laino):

ok!, that probability is closer to 1. Furthermore it can be rewritten as below: p= 96.86%

OpenStudy (anonymous):

ok that's it right?

OpenStudy (michele_laino):

yes!

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