Plz help Wendy throws a dart at this square-shaped target: Part A: Is the probability of hitting the black circle inside the target closer to 0 or 1? Explain your answer. (5 points) Part B: Is the probability of hitting the white portion of the target closer to 0 or 1? Explain your answer. (5 points)
what do you think?
ummm for part a 0?
true and the opposite for part b
ok
here we have to compute the area of the black circle
furthermore, we have to compute the area of the white square
ok
what is the area of the white square?
100
ok!
what is the area of the black circle? hint: you can use this value \[\pi = 3.14\]
I don't know what the radius is
the radius is half-diamter, so: radius = 2/2=...?
1
ok!
so what is the area of the circle?
it's 3.14
hint: \[area = \pi \times {\left( {radius} \right)^2}\]
ok!
now, the requested probability in part A, is given by the subsequent ratio: \[\large p = \frac{{area\;of\;the\;circle}}{{area\;of\;the\;square}} = ...?\]
since the favorable cases are given by the area of the black circle, whereas the possible cases are given by the area of the white square
0.0314
ok! We can write that probability in percentage form, so we have: p= 3.14 %
ok
Now, what is the difference between the area of the square and the area of the circle? Namely what is: 100-3.14=...?
96.86
ok! For the part A, we can say that the probability is closer to 0, since 0.0314 is closer to zero
ok
Finally, the requested probability in part B, is given by the subsequent formula: \[p = \frac{{area\;of\;the\;square - area\;of\;the\;circle}}{{area\;of\;the\;square}} = ...?\]
since, the favorable cases are given by the difference between those areas, whereas the possible cases are given by the area of the square
\[\Large \begin{gathered} p = \frac{{area\;of\;the\;square - area\;of\;the\;circle}}{{area\;of\;the\;square}} = \hfill \\ \\ = \frac{{96.86}}{{100}} = ...? \hfill \\ \end{gathered} \]
0.9686
ok!, that probability is closer to 1. Furthermore it can be rewritten as below: p= 96.86%
ok that's it right?
yes!
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