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OpenStudy (anonymous):
If it took 24.5 mL of .35 molar NaOH to neutralize 15 mL of HNO3 what is the molar concentration of the HNO3?
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OpenStudy (anonymous):
I've been told the answer is .572 M HNO3, but I have no idea how that answer was reached. Any help would be great! Thanks so much!
OpenStudy (dtan5457):
set them together (24.5 ml)(.35 M)=(15ml) (m2) this is from v1m1=m1m2
OpenStudy (dtan5457):
*v1m1=v2m2
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