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Mathematics 13 Online
OpenStudy (anonymous):

Help please, A force of 164 pounds makes an angle of 74 degrees 39 minutes with a second force. The resultant of the two forces makes an angle of 34 degrees 12 minutes to the first force. Find the magnitudes of the second force and of the resultant. (Please show steps, I have no idea how to do the steps please explain.)

OpenStudy (perl):

|dw:1429053021909:dw|

OpenStudy (perl):

|dw:1429053354262:dw|

OpenStudy (perl):

that is the diagram of whats going on i think

OpenStudy (anonymous):

OpenStudy (perl):

ok thats an equivalent drawing

OpenStudy (anonymous):

I'm more confused with steps the drawing part is fine

OpenStudy (perl):

A force of 164 pounds makes an angle of 74 degrees 39 minutes with a second force. The resultant of the two forces makes an angle of 34 degrees 12 minutes to the first force. Find the magnitudes of the second force and of the resultant. (Please show steps, I have no id F_1 = < 164 cos(0) , 164 sin(0) F_2 = < |F_2| cos (74 + 39/60) , |F_2| sin( 74 + 39/60)>

OpenStudy (perl):

$$ \large \rm { \vec F_1=( 164 cos(0~^o) , 164 sin(0~^o)) = (164, 0) \\\vec F_2 = ( |F_2| cos (74~^o + 39/60~^o) , |F_2| sin( 74~^o + 39/60~^o)) \\ Resultant = \vec F_1 + \vec F_2\\ \\ = ( 164,0) + ( |F_2| cos (74~^o +\frac{39}{60}~^o) , |F_2| sin( 74~^o + \frac{39}{60}~^o))\\ = ( 164+ |F_2| cos (74~^o + \frac{39}{60}~^o),~ 0 + |F_2| sin( 74~^o + \frac{39}{60}~^o))\\ = ( 164+ |F_2| cos (74~^o + \frac{39}{60}~^o), ~|F_2| sin( 74~^o + \frac{39}{60}~^o))\\ \\ \theta = arctan (\frac{ |F_2| sin( 74~^o + \frac{39}{60}~^o))}{164+ |F_2| cos (74~^o + \frac{39}{60}~^o)} \\ \therefore \\\\ 34+\frac{12}{60} =arctan (\frac{ |F_2| sin( 74~^o + \frac{39}{60}~^o))}{164+ |F_2| cos (74~^o + \frac{39}{60}~^o)} } $$

OpenStudy (perl):

solve for |F_2|

OpenStudy (anonymous):

34.2 = 15.14 ?

OpenStudy (perl):

take tan of both sides

OpenStudy (anonymous):

88.33= 15.14 is what I'm getting

OpenStudy (anonymous):

oh so F2= 121.4

OpenStudy (perl):

34 degrees 12 minute = 34 + 12/60 = 34.2 degrees 74 degrees and 39 minutes = 74 + 39/60 degrees = 74.65 degrees

OpenStudy (perl):

thats correct

OpenStudy (perl):

$$ \Large \rm { Resultant = \sqrt{|F_1|^2 + |F_2|^2} } $$

OpenStudy (anonymous):

my book says that the second force has a magnitude of 142 lb

OpenStudy (anonymous):

alright

OpenStudy (perl):

OpenStudy (anonymous):

got it written

OpenStudy (perl):

now see if you can find the magnitude of the resultant

OpenStudy (anonymous):

I got 244 but I have one a question on using the line of sines how would I find angles ACB and ABC of the figure from this problem?

OpenStudy (perl):

you want to use law of sines?

OpenStudy (anonymous):

yes

OpenStudy (perl):

so are you ok with the magnitude of the resultant?

OpenStudy (anonymous):

yes

OpenStudy (perl):

what idd you get

OpenStudy (anonymous):

244

OpenStudy (perl):

yes same here

OpenStudy (perl):

|dw:1429057531904:dw|

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