Solve Logarithm equation. Show work and explain.
30. log5 (x^2 + 7) = 2/3log5 64

Question

Solve Logarithm equation. Show work and explain.
30. log5 (x^2 + 7) = 2/3log5 64

firejay5 · Answer

@Hero

nnesha · Answer

same like previous question try it first

firejay5 · Answer

I did try it out and got x = -3 which is wrong

nnesha · Answer

show your work so i canlook over

firejay5 · Answer

haha no trust me plug -3 into the equation you get different answers

nnesha · Answer

it doesn't have to do anything about trust
i just said it bec i want to see where you did a mistake 
so we don't have to start it again that's it

firejay5 · Answer

wait hold on

firejay5 · Answer

it's right I had it right? (medal)

nnesha · Answer

right what ??
-3 ?? how did you get that ?

firejay5 · Answer

Really...............


x^2 + 7 = 64^2/3

sqrt of x^2 + 7 = sqrt 16

x+ 7 = 4
 
x = -3

nnesha · Answer

|dw:1429072639187:dw|
why did you take square of x^+7 
and at the end where did the square root of 7 gone ?