Question

What is the equation of a parabola that has a vertical axis, passes through the point (–1, 3), and has its vertex at (3, 2)?

x= –y2/16+6y/16–41/16

y= –x2/16+6x/16–41/16

y=x2/16–6x/16+41/16

x=y^2/16–6y/16+41/16

Answer 1

x= –y^2/16+6y/16–41/16

y= –x^2/16+6x/16–41/16

y=x^2/16–6x/16+41/16

x=y^2/16–6y/16+41/16

Answer 2

hey

Answer 3

\[x=-\frac{ x^2 }{ 16 }+\frac{ 6y }{ 16}-\frac{ 41 }{ 16}\]

Answer 4

Thats how a is set up

Answer 5

Okay.

Answer 6

The standard equation of a parabola is given by

Answer 7

yea

Answer 8

getting sleepy

Answer 9

trying to fight it

Answer 10

been waiting all night

Answer 11

Waiting for what? lol

Answer 12

I'm going to find this answer before I go to sleep and for the day over with

Answer 13

if I write your parabola as below:
y=ax^2+bx+c
then I can write this:
-b/2a=-1

Answer 14

so It is neither A or D

Answer 15

sorry, can you check your data?

Answer 16

if the vertical axis of your parabola has to pass at (-1,3), than the x-coordinate of the vertex has to be equal to -1

Answer 17

I was just looking at the x and y values

Answer 18

for example
or: