What is the equation of a parabola that has a vertical axis, passes through the point (–1, 3), and has its vertex at (3, 2)?

x= –y2/16+6y/16–41/16

y= –x2/16+6x/16–41/16

y=x2/16–6x/16+41/16

x=y^2/16–6y/16+41/16

Question

What is the equation of a parabola that has a vertical axis, passes through the point (–1, 3), and has its vertex at (3, 2)?

    x= –y2/16+6y/16–41/16

    y= –x2/16+6x/16–41/16

    y=x2/16–6x/16+41/16

    x=y^2/16–6y/16+41/16

anonymous · Answer

x= –y^2/16+6y/16–41/16

    y= –x^2/16+6x/16–41/16

    y=x^2/16–6x/16+41/16

    x=y^2/16–6y/16+41/16

anonymous · Answer

hey

anonymous · Answer

$$x=-\frac{ x^2 }{ 16 }+\frac{ 6y }{ 16}-\frac{ 41 }{ 16}$$

anonymous · Answer

Thats how a is set up

isaiah.feynman · Answer

Okay.

isaiah.feynman · Answer

The standard equation of a parabola is given by

anonymous · Answer

yea

anonymous · Answer

getting sleepy

anonymous · Answer

trying to fight it

anonymous · Answer

been waiting all night

isaiah.feynman · Answer

Waiting for what? lol

anonymous · Answer

I'm going to find this answer before I go to sleep and for the day over with

michele_laino · Answer

if I write your parabola as below:
y=ax^2+bx+c
then I can write this:
-b/2a=-1

anonymous · Answer

so It is neither A or D

michele_laino · Answer

sorry, can you check your data?

michele_laino · Answer

if the vertical axis of your parabola has to pass at (-1,3), than the x-coordinate of the vertex has to be equal to -1

anonymous · Answer

I was just looking at the x and y values

michele_laino · Answer

|dw:1429088353244:dw|
for example
or:
|dw:1429088410993:dw|