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Let f(x)=(6x^3-7)^3 and g(x)=6x^3-7 Given that f(x)=(h*g)(x), find h(x).
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So divide f(x) by g(x)
and you will have h(x)
\[f(x)/g(x)=h(x)\]
f(x) = (h*g)(x) f(x)=h(x)* g(x) f(x)/g(x)=h(x) now put the equation in it and solve for h(x).
thank you all
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\[(6x ^{3}-7)^{3}/(6x ^{3}-7)=( 6x ^{3}-7)^{2}\]
and that is your h(x)
thanks
thanks to openstudy
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