Mathematics
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OpenStudy (anonymous):
@jacob194485 ok one more
Factor completely −5x^3 + 10x^2.
A. Prime
B. −x(5x2 − 10x)
C. 5x(−x2 + 2x)
D. −5x2(x − 2)
but this time dont give me the answer i need to learn how to do it!_! plz!
11 years ago
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OpenStudy (anonymous):
i am tagging every one on my fans list lol
11 years ago
OpenStudy (anonymous):
@jordan123321 @Micah1mcdugle @roz_mar23 @MinightTheWolfie @alanwallace
11 years ago
OpenStudy (anonymous):
that r online
11 years ago
OpenStudy (bee_see):
what do they have in common?
11 years ago
OpenStudy (bee_see):
factor that out
11 years ago
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OpenStudy (anonymous):
the only thing i see is the x
11 years ago
OpenStudy (anonymous):
(-5) is common to both coefficients
x^2 is common to both variables
(- 5x^2) (x - 2)
11 years ago
OpenStudy (anonymous):
r u on the question or the answer choices
11 years ago
OpenStudy (anonymous):
the questions. that hasjust been explained
11 years ago
OpenStudy (anonymous):
now, to factor out, you must look at the two or more independent variables
11 years ago
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OpenStudy (anonymous):
you must check for the co-efficient and also the powers
11 years ago
OpenStudy (anonymous):
THE X'S ?
11 years ago
OpenStudy (anonymous):
yes, x is the independent variable separated by + sign. now note before u can factor out, there must be a separation with either + or -
11 years ago
OpenStudy (anonymous):
R THE INDEPENDENT VARIABLES THE X'S?
11 years ago
OpenStudy (anonymous):
ohh ohkay
11 years ago
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OpenStudy (anonymous):
the variable involved is just X
11 years ago
OpenStudy (anonymous):
now, lets look at some examples before working on that,.....
facor out ..
\[x ^{4}+x\]
11 years ago
OpenStudy (anonymous):
can you try factorize that?
11 years ago
OpenStudy (anonymous):
ok i will try
11 years ago
OpenStudy (anonymous):
x(x^4)??
11 years ago
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OpenStudy (anonymous):
hmmmm.wrong
11 years ago
OpenStudy (anonymous):
now have you heard of distribution property?
11 years ago
OpenStudy (anonymous):
distribution property states that a(b+c)=ab +ac
11 years ago
OpenStudy (anonymous):
its just a way of opening the bracket
11 years ago
OpenStudy (anonymous):
ummm ive hered tha but i thought it was a+b=c^2
11 years ago
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OpenStudy (anonymous):
nooooooo
11 years ago
OpenStudy (anonymous):
it says that 2(1+3) is same as 2(1)+2(3)
11 years ago
OpenStudy (anonymous):
i am sooo soorry for being so dumb and frustrating
11 years ago
OpenStudy (anonymous):
lol
11 years ago
OpenStudy (anonymous):
try that and tell me if u get thesame thing
11 years ago
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OpenStudy (anonymous):
yes is that the foil presedure
11 years ago
OpenStudy (anonymous):
just a start to it
11 years ago
OpenStudy (anonymous):
now, look at \[x ^{4} +x\]
11 years ago
OpenStudy (anonymous):
ok i am looking lol
11 years ago
OpenStudy (anonymous):
first, they are asking if there is a common thing between x^4 and x
11 years ago
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OpenStudy (anonymous):
the x
??
11 years ago
OpenStudy (anonymous):
now recal that the things to watch out are 1) the variables and power,
@
2) the co-efficient of the two separated variables
11 years ago
OpenStudy (anonymous):
now, what is the co-efficient of x^4?
11 years ago
OpenStudy (anonymous):
you there?
11 years ago
OpenStudy (anonymous):
do you have idea?
11 years ago
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OpenStudy (anonymous):
sorry had to do something
11 years ago
OpenStudy (anonymous):
can you answer the question ?
11 years ago
OpenStudy (anonymous):
what is the co-efficient of x^4?
11 years ago
OpenStudy (anonymous):
i am not sure
11 years ago
OpenStudy (anonymous):
i am so confused i will give you medal any way
11 years ago
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OpenStudy (anonymous):
please stay let me teach you and i promise you will understand. never give up
11 years ago
OpenStudy (anonymous):
@i<3u43v4
11 years ago
OpenStudy (anonymous):
i am triing but it is hard i hat f*cking school
ok go on
11 years ago
OpenStudy (anonymous):
the co-efficient of a variable is the number beside or multiplying that veriable
11 years ago
OpenStudy (anonymous):
5x. the co-effiecient of that 5x or x is the 5
11 years ago
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OpenStudy (anonymous):
so it is 4
11 years ago
OpenStudy (anonymous):
here the co-effiecient of \[x ^{4}\]
11 years ago
OpenStudy (anonymous):
is 1
11 years ago
OpenStudy (anonymous):
there is no number 1 tho
11 years ago
OpenStudy (anonymous):
note this, every variable or number is multiplied by invisible 1 and devided by invisible 1
11 years ago
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OpenStudy (anonymous):
e.g \[1x/1\]
11 years ago
OpenStudy (anonymous):
ok so it is always 1 right?
11 years ago
OpenStudy (anonymous):
but in maths is better to say x instead of 1x/1
11 years ago
OpenStudy (anonymous):
i have a question for you. \[2\times1=\]
11 years ago
OpenStudy (anonymous):
ok
11 years ago
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OpenStudy (anonymous):
2
11 years ago
OpenStudy (anonymous):
any thing times 1 is it self
11 years ago
OpenStudy (anonymous):
now what that means is that 2 is times d by 1 and at the same time divided by 1, this is how it ought to be \[(2\times1)\div1\]
11 years ago
OpenStudy (anonymous):
but in maths we will just take 2 rather than\[ (2\times 1)\div1\]
11 years ago
OpenStudy (anonymous):
now did you understand that step?
11 years ago
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OpenStudy (anonymous):
did you understand why we always say 2 instead of (2X1)/1?
11 years ago
OpenStudy (anonymous):
waw. later den
11 years ago
OpenStudy (anonymous):
yes i under stand now!!
11 years ago
OpenStudy (anonymous):
it is d?
11 years ago
OpenStudy (anonymous):
@GIL.ojei
11 years ago
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OpenStudy (anonymous):
yap
11 years ago
OpenStudy (anonymous):
THX
11 years ago
OpenStudy (anonymous):
thanks to openstudy.
11 years ago
OpenStudy (anonymous):
Sorry i never got the notification if you still need the answer its −5x2(x − 2)
11 years ago