Question

**WILL MEDAL**
Janine inflated 1 ball to a radius of 18 cm and another ball to a radius of 12 cm.

How much more air was in the larger ball?
Use 3.14 to approximate pi and express your answer in hundredths.

___cm3

Answer 1

well the volume of a sphere is 4/3pir^3
so you would take the volume of both and then take the difference

Answer 2

So 129.5567

Answer 3

Difference in volume is given by \[V-v = \frac{ 4 }{ 3 }\pi R^{3} - \frac{ 4 }{3 } \pi r^{3}\]

Answer 4

well i got a different answer
i did
4/3pi(18)^3 - 4/3pi(12)^3
is this what you did

Answer 5

Im confused

Answer 6

We can then simplify by doing, \[V-v = \frac{ 4 }{ 3 }\pi(R^{3}-r^{3})\]

Answer 7

Where big r is the radius of the big ball and small r is the radius of the small ball.

Answer 8

Im still confused whats the answer?

Answer 9

well
just take it step by step
18^3-12^3 is what

Answer 10

5832-1728

Answer 11

and that is 4104

Answer 12

the just multiply that by 4 then divide by 3

Answer 13

after that multiply by pi

Answer 14

17182.08?

Answer 15

@MelodicSymphony

Answer 16

haha i think so

Answer 17

just checked you are right

Answer 18

Thx ill tell u in like 3 mins what i get