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Chemistry 27 Online
OpenStudy (anonymous):

Determine the volume of one mole of an ideal gas at 25 degrees celsius and 0.915 kPa/

OpenStudy (kaibaseto):

Since you are using the ideal gas law with the pressure in kelvins the constant must be 8.31

OpenStudy (anonymous):

well the ideal gas law states PV=nRT but the temperature has to be in Kelvin so add 273 to convert celcius to Kelvin so itd be .915kPa(V)=1(8.314)(298)

OpenStudy (kaibaseto):

Correction: I meant the pressure is in kilopascals (kPa) so therefore the constant must be 8.31 L* kPa/K * mols

OpenStudy (anonymous):

So if you change it to atm would the constant be .0821?

OpenStudy (anonymous):

Would that change the answer?

OpenStudy (kaibaseto):

The number would only change a small amount. However for the most part it will end up pretty much the same except for the ones and the decimal's places.

OpenStudy (anonymous):

Thank you very much! You guys helped a lot. :) Oh but one quick thing... how do you know how many significant digits to put in your answer? I always get tripped up on that part.

OpenStudy (anonymous):

well it is by the least amount of significant figures in the problem usually so this one would be 3 sig figs

OpenStudy (anonymous):

Ok thank you very much!

OpenStudy (anonymous):

How do you find n in an ideal gas law equation?

OpenStudy (anonymous):

well you solve for the variable so pv=nrt would then be pv/rt=n

OpenStudy (anonymous):

Thanks!!! :)

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