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OpenStudy (anonymous):
\[3\]
OpenStudy (anonymous):
oops
OpenStudy (anonymous):
sorry
OpenStudy (anonymous):
it ok
OpenStudy (anonymous):
but can u help me andrew
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OpenStudy (anonymous):
@perl
OpenStudy (anonymous):
@jigglypuff314
jigglypuff314 (jigglypuff314):
First find the first derivative :)
can you do that? and what would you get?
OpenStudy (anonymous):
3x^2+18
jigglypuff314 (jigglypuff314):
oh wait...
hmmm
are you sure that is the proper function?
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OpenStudy (anonymous):
yes.
jigglypuff314 (jigglypuff314):
ok :/
Critical Points are when the first derivative is equal to 0
jigglypuff314 (jigglypuff314):
3x^2 + 18 = 0
does x equal any real numbers?
OpenStudy (anonymous):
i think it does
jigglypuff314 (jigglypuff314):
then what would x equal?
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OpenStudy (anonymous):
i thnik 9 im nt really sure
jigglypuff314 (jigglypuff314):
3x^2 = -18
x^2 = -6
a squared number cannot equal a negative number (without being imaginary)
therefore there are no real values of x
so there are no Critical Numbers
OpenStudy (anonymous):
ok that make sense i see how you got that .
OpenStudy (anonymous):
but how do you determine when a interval is increasing or decreasing my teacher never thought that
OpenStudy (anonymous):
really confused
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jigglypuff314 (jigglypuff314):
interval is increasing when the derivative is positive
interval is decreasing when the derivative is negative
OpenStudy (anonymous):
so there is no increase since we got negatives when we did the derivatives
jigglypuff314 (jigglypuff314):
not quite ^_^
the "no critical points" that we got just means that there are no changes from positive to negative or negative to positive
(it means that the function is either always increasing or always decreasing)
so just plug in a random number (like 0) into the derivative
3x^2 + 18
and tell me if you get a positive number or a negative number :)
OpenStudy (anonymous):
wouldn't it be positive
jigglypuff314 (jigglypuff314):
that's right!
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jigglypuff314 (jigglypuff314):
so it would Always be Increasing :)
OpenStudy (anonymous):
but can it be decreasing at the same time
jigglypuff314 (jigglypuff314):
hmm no, I don't think so :)
OpenStudy (anonymous):
so how do you know when it decreasing
jigglypuff314 (jigglypuff314):
if the number was negative, it would be decreasing
but that never happens
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OpenStudy (anonymous):
so in this problem would it only be increasing ?
jigglypuff314 (jigglypuff314):
yes :)
OpenStudy (anonymous):
how would i determine the relative extrema
jigglypuff314 (jigglypuff314):
:/
relative extrema happen at the critical points
which we don't have
OpenStudy (anonymous):
hank you for the help really appreciate. Can you help me with another question
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