Trigonometry
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OpenStudy (anonymous):
prove the identity \[2\cos 2\theta+1=\sin \theta \]
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OpenStudy (misty1212):
?
OpenStudy (misty1212):
really not clear
maybe the equation editor would help
OpenStudy (anonymous):
\[2\cos 2\Theta +1=\sin \Theta\]
OpenStudy (misty1212):
that would be pretty much of a miracle
OpenStudy (xapproachesinfinity):
are you sure that is how it is written
\[\]
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OpenStudy (anonymous):
no i mean like prove how its true
OpenStudy (misty1212):
since for example if \(\theta=0\) the left side is 3 and the right side is 0
OpenStudy (xapproachesinfinity):
something is wrong with your equation mu friend
OpenStudy (anonymous):
not solve it i.e. 1/cos=sec ;1/cos=1/cos
OpenStudy (xapproachesinfinity):
an identity has to be true for any x( or other variable you are using)
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OpenStudy (anonymous):
it is not an identity
in fact it may never be true
OpenStudy (lurker):
:>
OpenStudy (xapproachesinfinity):
you cannot prove something that is not an identity
OpenStudy (xapproachesinfinity):
the other question you asked has the same problem
Nnesha (nnesha):
\[2\cos^2 \theta +1 \] ??
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OpenStudy (xapproachesinfinity):
when you say prove we expecting that it is true
and we want a way to show it is
so careful about the question you are asking
OpenStudy (anonymous):
its already true we just need to show it
OpenStudy (xapproachesinfinity):
what you wrote cannot be achieved in any way using those identities
OpenStudy (anonymous):
oh it is true somewhere i lied
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OpenStudy (xapproachesinfinity):
where is it true?
OpenStudy (anonymous):
explain please
OpenStudy (xapproachesinfinity):
again if it true for some values, it does not mean it is identity
OpenStudy (anonymous):
good luck solving that equation...
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OpenStudy (xapproachesinfinity):
eh that is really beyond the question @satellite73
OpenStudy (xapproachesinfinity):
hahaha
OpenStudy (anonymous):
.-. its on the worksheet itself it says demonstrate that each identity is true
OpenStudy (xapproachesinfinity):
well, the question is wrong itself
and good luck in answering it :)
OpenStudy (xapproachesinfinity):
if you did "prove it" we would love to see how
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OpenStudy (anonymous):
maybe there is a typo in the question
OpenStudy (xapproachesinfinity):
the most basic approach to check is what @misty1212 tried from the beginning
when x=0
you will get 3=0 ? and decide for yourself does that make sense