Question

Solve the following systems of equations.

x^2+y^2=16
x+y=4

Answer 1

Isolate one of the variables in one equation, then substitute the "isolated variable" equation you get into the other original equation.
example:\[x=-y+4\]\[(-y+4)^{2}+y^{2}=16\]\[\text{solve for }y\]

Answer 2

After that, it becomes easier to solve for the other variable. :)

Answer 3

where did you get y^2

Answer 4

It's part of one of the original equations.\[x^{2}+y^{2}=16\text{, if you isolate x in the other equation, you can replace the }x\text{ in this equation}\]

Answer 5

*you can replace the x in this equation

Answer 6

Basically, the substitution method, you know what I mean?

Answer 7

yes

Answer 8

Okay, so do you know where to go from here?

Answer 9

y=0

Answer 10

o-o
You solved and got that?

Answer 11

yes

Answer 12

x=4 y=0

Answer 13

well x=4 y=0 is a valid result but the answer can also be x=0 y=4

Answer 14

Since you can isolate y instead of x which would cause the second set of answers

if you want whole #'s that is
because you could also do:\[\sqrt{8}^{2}+\sqrt{8}^{2}=16\]