Solve the following systems of equations.

x^2+y^2=16
x+y=4

Question

Solve the following systems of equations.

x^2+y^2=16
x+y=4

kittiwitti1 · Answer

Isolate one of the variables in one equation, then substitute the "isolated variable" equation you get into the other original equation.
example:$$x=-y+4$$$$(-y+4)^{2}+y^{2}=16$$$$\text{solve for }y$$

kittiwitti1 · Answer

After that, it becomes easier to solve for the other variable. :)

anonymous · Answer

where did you get y^2

kittiwitti1 · Answer

It's part of one of the original equations.$$x^{2}+y^{2}=16\text{, if you isolate x in the other equation, you can replace the }x\text{ in this equation}$$

kittiwitti1 · Answer

*you can replace the x in this equation

kittiwitti1 · Answer

Basically, the substitution method, you know what I mean?

anonymous · Answer

yes

kittiwitti1 · Answer

Okay, so do you know where to go from here?

anonymous · Answer

y=0

kittiwitti1 · Answer

o-o
You solved and got that?

anonymous · Answer

yes

anonymous · Answer

x=4 y=0

kittiwitti1 · Answer

well x=4 y=0 is a valid result but the answer can also be x=0 y=4

kittiwitti1 · Answer

Since you can isolate y instead of x which would cause the second set of answers

if you want whole #'s that is
because you could also do:$$\sqrt{8}^{2}+\sqrt{8}^{2}=16$$