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Mathematics 22 Online
OpenStudy (anonymous):

how do you find the amplitude and period of f(t)=-tan 0.4 t

OpenStudy (amistre64):

memorization ... its basically memorization

OpenStudy (amistre64):

the absolute value of the number multiplying your trig function is your amp the argument itself helps define the period; tan has a normal period at pi sooo tan(.4 t) = tan(pi) when: .4 t = pi , for what value of t does this happen?

OpenStudy (anonymous):

you have to multiply t?

OpenStudy (amistre64):

well, id divide by .4 but thats just me

OpenStudy (anonymous):

oh ok so divide t by 4

OpenStudy (amistre64):

.4 t = pi /.4 /.4 t = pi/.4 which of course needs to be simplified since we dont really like haveing a decimal on the bottom of a fraction ....

OpenStudy (anonymous):

and it would be 2? when you simplify

OpenStudy (amistre64):

pi/.4 = 10pi/4 = 5pi/2 or simply 2.5 pi

OpenStudy (anonymous):

but whats the amplitude and period

OpenStudy (amistre64):

i do believe ive already commented on that up above ...

OpenStudy (amistre64):

from the information provided, what would you conclude is the amp and period?

OpenStudy (anonymous):

2.5?

OpenStudy (amistre64):

2.5 pi , is what?

OpenStudy (anonymous):

the amp?

OpenStudy (amistre64):

no .... which means its got to be the period by default. tan has a normal period of pi, which means that tan(.4 t) = tan(pi) .4 t = pi when t = 2.5pi ... which gives us the adjusted period of the function

OpenStudy (anonymous):

thats not even an answer

OpenStudy (amistre64):

it is an answer ... or do you mean thats not an option to choose

OpenStudy (anonymous):

thats not an option to chose

OpenStudy (amistre64):

then which option does it equate with? i cant see you options from where im at ...

OpenStudy (amistre64):

also, did you type the question correctly? is it .4 t or 4t ?

OpenStudy (anonymous):

a says amp:1 period:5pi/2 b says amp:none ped:5pi/2 c says amp: 1 prd. 2pi d says amp:none prd:2pi

OpenStudy (amistre64):

and you really didnt read anything i posted did you ... pi/.4 = 10pi/4 = 5pi/2 or simply 2.5 pi isnt it an option?

OpenStudy (anonymous):

i did read what you said but it doesnt make sense

OpenStudy (amistre64):

pi/.4 = 10pi/4 = 5pi/2 these are all equivalent values, its called simplification. usually if they have a decimal point in the problem they want a decimal point in the solution so i just took it one step further.

OpenStudy (amistre64):

but as the options point out; 5pi/2 is a reasonable 'answer'

OpenStudy (amistre64):

the only ting to consider is the amplitude to determine which option they want

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