how do you find the amplitude and period of f(t)=-tan 0.4 t
memorization ... its basically memorization
the absolute value of the number multiplying your trig function is your amp the argument itself helps define the period; tan has a normal period at pi sooo tan(.4 t) = tan(pi) when: .4 t = pi , for what value of t does this happen?
you have to multiply t?
well, id divide by .4 but thats just me
oh ok so divide t by 4
.4 t = pi /.4 /.4 t = pi/.4 which of course needs to be simplified since we dont really like haveing a decimal on the bottom of a fraction ....
and it would be 2? when you simplify
pi/.4 = 10pi/4 = 5pi/2 or simply 2.5 pi
but whats the amplitude and period
i do believe ive already commented on that up above ...
from the information provided, what would you conclude is the amp and period?
2.5?
2.5 pi , is what?
the amp?
no .... which means its got to be the period by default. tan has a normal period of pi, which means that tan(.4 t) = tan(pi) .4 t = pi when t = 2.5pi ... which gives us the adjusted period of the function
thats not even an answer
it is an answer ... or do you mean thats not an option to choose
thats not an option to chose
then which option does it equate with? i cant see you options from where im at ...
also, did you type the question correctly? is it .4 t or 4t ?
a says amp:1 period:5pi/2 b says amp:none ped:5pi/2 c says amp: 1 prd. 2pi d says amp:none prd:2pi
and you really didnt read anything i posted did you ... pi/.4 = 10pi/4 = 5pi/2 or simply 2.5 pi isnt it an option?
i did read what you said but it doesnt make sense
pi/.4 = 10pi/4 = 5pi/2 these are all equivalent values, its called simplification. usually if they have a decimal point in the problem they want a decimal point in the solution so i just took it one step further.
but as the options point out; 5pi/2 is a reasonable 'answer'
the only ting to consider is the amplitude to determine which option they want
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