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Mathematics 13 Online
OpenStudy (anonymous):

How far from the base of a pyramid of altitude 10m is a section parallel to the base and equal in area to half of the base?

OpenStudy (anonymous):

@perl

OpenStudy (perl):

|dw:1429278918220:dw|

OpenStudy (perl):

Because of similarity A1 / A2 = (L1 / L2 )^2

OpenStudy (perl):

that was a generic pyramid, you dont need to use that specific pyramid

OpenStudy (perl):

|dw:1429279141340:dw|

OpenStudy (perl):

$$ \Large { \frac{A_1}{A_2} = \left (\frac{L_1}{L_2} \right)^2 \\ \therefore \\ \frac{A_1}{\frac12 A_1} = \left (\frac{10}{L_2} \right)^2 } $$

OpenStudy (perl):

note that you can cancel A_1

OpenStudy (anonymous):

volume of pyramid is 1/3Bh Vw/Vp = (hw/hp)^3???

OpenStudy (perl):

$$ \Large { \frac{A_1}{A_2} = \left (\frac{L_1}{L_2} \right)^2 \\ \therefore \\ \frac{A_1}{\frac12 A_1} = \left (\frac{10}{L_2} \right)^2 \\ \therefore \\ \frac{\cancel{A_1}}{\frac12 \cancel{A_1}} = \left (\frac{10}{L_2} \right)^2 \\ \therefore \\ \frac{1}{\frac12 } = \left (\frac{10}{L_2} \right)^2 \\ \therefore \\ 2 = \left (\frac{10}{L_2} \right)^2 \\ \therefore \\ 2 = \frac{10^2}{L_2~^2} \\ \therefore \\ {L_2~^2} = \frac{10^2}{2} \\ \therefore \\ L_2 = \sqrt {\frac{10^2}{2 }} } $$

OpenStudy (perl):

|dw:1429279708702:dw|

OpenStudy (anonymous):

5sqrt of 2

OpenStudy (perl):

|dw:1429279776683:dw|

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