Question

A regular triangular pyramid with a slant height of 9m has a volume equal to 50 m ^3 . Find the lateral area of the pyramid.

Answer 1

@perl

Answer 2

i have 10 more problems here, :D

Answer 3

V = 1/3 * Base * height

Answer 4

Lateral surface area = 1/2 * perimeter of base * slant height.
LSA = 1/2 * (3x) * 9

we need to find a side of the base triangle

Answer 5

using the fact that volume = 50

Answer 6

the base area is an equaliteral triangle. therefore if the side is x, the area
sqrt(3)/4 x^2

now plug this into volume equation
V = 1/3 * Base_area * altitude
50 = 1/3 * (sqrt(3)/4 x^2) * a

we can find an expression for altitude.