Question

Can someone help me make up a quadratic equation that has two real zeros? PLEASE

Answer 1

Sure :)

Answer 2

I have no idea how to though

Answer 3

I know that the formula is \[Ax ^{2} + Bx + C = 0\]

Answer 4

@3.14159Vikki

Answer 5

a possible equation, is:
\[\left( {x - a} \right)\left( {x - b} \right) = 0\]
where a, and b are the zeroes of that equations, namely they are real numbers

Answer 6

So I can substitute any number in for x?

Answer 7

developing that formula, we get:
x^2-(a+b)x+ab=0
so, comparing with your formula, we get:
A=1,
B=-(a+b),
C=a*b

Answer 8

Thats confusing

Answer 9

yes!, since it is a quadratic function of x

Answer 10

This is what I have to do
You are going to write a fairy tale! Your story should include all of the standard elements of fairy tales.

Begins “Once upon a time … ”
Animals can act like humans.
Involves magical items or helpers.
Ends “ … happily ever after.”
Your story must also fully cover these math concepts. This is an educational fairy tale … the best kind!

Create a quadratic function with two real zeros.
Solve a system of non-linear equations with a graph.
Solve a system of non-linear equations with a table.
Compare linear, quadratic, and exponential growth functions using a table and a graph. Submit the graph and table.
Identify that exponential functions exceed linear and quadratic functions.
You may present your fairy tale as a document, a slideshow presentation, a comic book, a video, or other medium. Any steps or work must be shown.

Answer 11

we have:
\[\left( {x - a} \right)\left( {x - b} \right) = {x^2} - \left( {a + b} \right)x + ab = 0\]

Answer 12

How do you get the second part of the equation?

Answer 13

I have applied the distributive property of multiplication, over addition

Answer 14

Oh okay well can you help me with the instructions that I copied and pasted

Answer 15

ok!

Answer 16

please wait a moment

Answer 17

okay

Answer 18

we can consider the subsequent system:
\[\left\{ \begin{gathered}
{x^2} + {y^2} = 25 \hfill \\
y = 2x - 1 \hfill \\
\end{gathered} \right.\]

Answer 19

@jewelshipp

Answer 20

I don't know what that means I'm doing algebra 1 online and it doesn't explain things very well

Answer 21

@Michele_Laino

Answer 22

in that system we are looking for the intersection between a circumference whose radius is r=5, and whose center is (0,0) namely the origin, and the line whose equation is y=2x-1

Answer 23

I didn't learn anything about circles in this module or lesson

Answer 24

do you know the equation of a parabola?

Answer 25

Ax^2 + Bx + C = 0

Answer 26

better is:
y=Ax^2+Bx+C

Answer 27

Okay now i think all its asking is for me to substitute A, B, and C right?

Answer 28

yes! Nevertheless in order to apply that procedure, I have to give you three point, at least

Answer 29

Yes

Answer 30

But when you put it in the quadratic equation it has to have two real zeros

Answer 31

the number of the real zeroes of a quadratic equation, depends on the value of this quantity:
B^2-4*A*C
if that quantity is greater than or equal to zero, then we have 2 real zeroes.
more precisely
if B^2-4*A*C >0, then we have 2 distinct real zeroes,
if B^2-4*A*C=0 then we have 2 identical real zeroes
whereas if:
B^2-4*A*C <0, then we have no real zeroes, namely the 2 zeroes are complex conjugate numbers

Answer 32

so i do \[B^2-4\times AC <0\]

Answer 33

oh wait no

Answer 34

no we have to request that thie subsequent condition hods:
\[\Large {B^2} - 4AC \geqslant 0\]

Answer 35

holds*

Answer 36

okay can i substitute any number or do they have to be certain numbers?

Answer 37

you have to have certain numbers, since the quantities:
A, B, abd C are parameters, and not variables

Answer 38

what numbers then?

Answer 39

dempends on the exercise that you have to solve. For example
if we have:
A=1, B=-6, and C=8
we get:
\[A{x^2} + Bx + C = {x^2} - 6x + 8\]

Answer 40

depends]

Answer 41

There isn't a certain situation its just a random thing that i have to make

Answer 42

please can you give me an example?

Answer 43

I don't have one

Answer 44

I just have to make a fairy tail using math

Answer 45

Is this what they call a "QH question"?

Answer 46

I have no idea

Answer 47

I don't even know what a QH question is

Answer 48

Qualified helpers?

Answer 49

Oh yeah

Answer 50

I mean you must have paid to ask this, right?

Answer 51

yes because i cant find the answer anywhere

Answer 52

I think that every question deserves attention @ParthKohli

Answer 53

All i need is someone to make up a quadratic equation for me

Answer 54

I give you an example fro geometry. Is it ok?

Answer 55

from*

Answer 56

I don't think i will get it because i havn't taken geometry

Answer 57

I can give you an example from physics, then

Answer 58

im in 8th grade dude