Question

please help! question below.

Answer 1

http://gyazo.com/6645182789279f0e49a33f8feced48c7

Answer 2

Jim can win if Helen flips a tail and Jim flips a head : 1/2*1/2

or

if Helen flips a tail again and Jim flips a head : (1/2*1/2)*1/2*1/2

or

if Helen flips a tail again and Jim flips a head : (1/2*1/2*1/2*1/2)*1/2*1/2

....

Answer 3

so the probability for Jim winning is given by
\[\frac{1}{4}+\frac{1}{4^2}+\frac{1}{4^3}+\cdots\]

Answer 4

how do i find that sum?

Answer 5

its a converging geometric series

Answer 6

I know what both those terms mean, but I am unfamiliar with how to calculate it, sorry...

Answer 7

http://f.tqn.com/y/statistics/1/W/9/0/-/-/geometric.jpg

Answer 8

a = 1/4
r = 1/4

plug and chug

Answer 9

It's \[\huge \frac{\frac{1}{4}}{1-\frac{1}{4}}\] or \[\huge \frac{\frac{1}{4}}{\frac{3}{4}}=\frac{1}{3}\]

Answer 10

looks good

Answer 11

Great! Thanks, so this is not a fair game, right?

Answer 12

Clearly the one who flips the coin first has an advantage

Answer 13

ok, got it. The final answer would thus be \[\huge (1,3)\] right?

Answer 14

Yep!

Answer 15

ok, great! thanks

Answer 16

np :)