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jimthompson5910 (jim_thompson5910):
Draw the rim
|dw:1429408272610:dw|
jimthompson5910 (jim_thompson5910):
Draw the ball inside. Make sure the two circles have the same center point
|dw:1429408300192:dw|
jimthompson5910 (jim_thompson5910):
"What is the distance between the ball and the rim in a shot in which the ball goes exactly in the center of the rim?"
so they want this distance
|dw:1429408336569:dw|
OpenStudy (ayyookyndall):
Is there an equation I can use?
jimthompson5910 (jim_thompson5910):
"The diameter of a basketball rim is 18 inches"
|dw:1429408379117:dw|
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jimthompson5910 (jim_thompson5910):
"A standard basketball has a circumference of 30 inches"
what is the diameter of the ball?
jimthompson5910 (jim_thompson5910):
I'll be right back
OpenStudy (ayyookyndall):
The diameter of the ball is 15
OpenStudy (ayyookyndall):
Whats next?
OpenStudy (ayyookyndall):
@jim_thompson5910
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OpenStudy (anonymous):
circumference = \[2\pi r\]
jimthompson5910 (jim_thompson5910):
C = 2*pi*r like DarkBerrt points out
30 = 2*pi*r
r = ???
OpenStudy (anonymous):
or
this might be easier for this question: c= pi*D
OpenStudy (ayyookyndall):
So
C = 2 * pi * r
30 = 2 * pi * r
How do I find r?
OpenStudy (anonymous):
use a calculator
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OpenStudy (ayyookyndall):
No duh. What do I do to find r?
jimthompson5910 (jim_thompson5910):
divide both sides by 2pi to isolate r
OpenStudy (ayyookyndall):
So 30 / 3.14?
OpenStudy (anonymous):
c=2*pi*r
30=2*pi*r
15=pi*r
now use calculator since question doesn't ask in terms of pi
OpenStudy (ayyookyndall):
30 = 2 * pi * r
*Divide pi by both sides*
9.55414013 rounds to 9.6
9.6 = 2
*Subtract 2 on both sides*
9.6 - 2 = 7.6
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OpenStudy (ayyookyndall):
Like that? @jim_thompson5910 @DarkBerrt
OpenStudy (anonymous):
step one is perfect; now step 2..... where did the r go??