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Mathematics 18 Online
OpenStudy (ayyookyndall):

Help Needed!

jimthompson5910 (jim_thompson5910):

Draw the rim |dw:1429408272610:dw|

jimthompson5910 (jim_thompson5910):

Draw the ball inside. Make sure the two circles have the same center point |dw:1429408300192:dw|

jimthompson5910 (jim_thompson5910):

"What is the distance between the ball and the rim in a shot in which the ball goes exactly in the center of the rim?" so they want this distance |dw:1429408336569:dw|

OpenStudy (ayyookyndall):

Is there an equation I can use?

jimthompson5910 (jim_thompson5910):

"The diameter of a basketball rim is 18 inches" |dw:1429408379117:dw|

jimthompson5910 (jim_thompson5910):

"A standard basketball has a circumference of 30 inches" what is the diameter of the ball?

jimthompson5910 (jim_thompson5910):

I'll be right back

OpenStudy (ayyookyndall):

The diameter of the ball is 15

OpenStudy (ayyookyndall):

Whats next?

OpenStudy (ayyookyndall):

@jim_thompson5910

OpenStudy (anonymous):

circumference = \[2\pi r\]

jimthompson5910 (jim_thompson5910):

C = 2*pi*r like DarkBerrt points out 30 = 2*pi*r r = ???

OpenStudy (anonymous):

or this might be easier for this question: c= pi*D

OpenStudy (ayyookyndall):

So C = 2 * pi * r 30 = 2 * pi * r How do I find r?

OpenStudy (anonymous):

use a calculator

OpenStudy (ayyookyndall):

No duh. What do I do to find r?

jimthompson5910 (jim_thompson5910):

divide both sides by 2pi to isolate r

OpenStudy (ayyookyndall):

So 30 / 3.14?

OpenStudy (anonymous):

c=2*pi*r 30=2*pi*r 15=pi*r now use calculator since question doesn't ask in terms of pi

OpenStudy (ayyookyndall):

30 = 2 * pi * r *Divide pi by both sides* 9.55414013 rounds to 9.6 9.6 = 2 *Subtract 2 on both sides* 9.6 - 2 = 7.6

OpenStudy (ayyookyndall):

Like that? @jim_thompson5910 @DarkBerrt

OpenStudy (anonymous):

step one is perfect; now step 2..... where did the r go??

jimthompson5910 (jim_thompson5910):

|dw:1429409903666:dw|

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