How do you solve this problem? The question is attached as an image. I'm not sure how to break up the function into shapes or elementary figures.
\[\int_{-4}^{5} f(x)dx = \int_{-4}^{-2} f(x)dx +\int_{-2}^{0} f(x)dx + \int_{0}^{5} f(x)dx\] Now just find teh equation of line AB, BC and CD, then calculate the integral above.
um for the equation of the lines i got -5/2x -1 for BC, 3x+10 for AB, and 2/5x -1 for CD and i got the x-intercepts as -2/5, -10/3 and 5/2
but what exactly are you supposed to do next? i'm kind of new to integrals
check out this nice picture http://www.wolframalpha.com/input/?i=line+segment+%28-4%2C-2%29%2C%28-2%2C4%29++and+line+segment+%28-2%2C4%29%2C+%280%2C-1%29+and+line+segment+%280%2C-1%29%2C%285%2C1%29
yeah i drew the picture but i was confused as to how to break it up into shapes
Now integrate the equation of line AB from x = -4 to x = -2 Sum with the integral of line BC from x = -2 to x = 0 Sum with the integral of line CD from x = 0 to x = 5
wait how exactly do you find the integral of line BC from x = -2 to x = 0? do you have to break it up into shapes and find the area under and over the line or is there another method?
look up the closed questions from yesterday asker Math2400 can someone explain how i would go about this?
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