Ask your own question, for FREE!
Mathematics 16 Online
OpenStudy (anonymous):

Help please, Is the length x of the obtuse triangle in the diagram below to three significant figures is 5.43 cm. (attached figure)

OpenStudy (anonymous):

OpenStudy (reynad):

We can use a trig rule. Do you know which one?

OpenStudy (anonymous):

No I'm not sure to be honest.

OpenStudy (anonymous):

wouldn't you just use the Pythagorean theorem to solve for x? is it asking to prove that x = 5.43 cm?

OpenStudy (anonymous):

It's asking if it's true or false

OpenStudy (anonymous):

so then do a^2 + b^2 = c^2, solve for x and the value will tell you if it's true or false

OpenStudy (anonymous):

so x^2 + 8.90^2 = 14.2^2 x^2 = 14.2^2 - 8.90^2 x^2 = 201.64 - 79.21 x^2 = 122.43 sqrt(x^2) = sqrt(122.43) x = 11.064809081

OpenStudy (anonymous):

ah ok thanks!

OpenStudy (anonymous):

no prob!

OpenStudy (reynad):

you can't do Pythagorean because it's not a right angled triangle

OpenStudy (anonymous):

then how would you solve it?

OpenStudy (anonymous):

my bad. you would use the sine law to find the angle opposite the side 14.2, then find the third angle in the triangle using 180-angles, then use sine law to solve for x

OpenStudy (anonymous):

did not see that it was an obtuse triangle

OpenStudy (anonymous):

so then it's true?

OpenStudy (reynad):

you can also do the cosine law but sine law works fine

OpenStudy (anonymous):

I got the answer to be true is that wrong?

OpenStudy (anonymous):

I got two different solutions a=5.43 and a=22.53

OpenStudy (anonymous):

how did you come across these solutions? and I'm assuming if you got the answer that is stated in the question, it should be true?

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!