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In triangle ABC, what is the measure of c if a = 12, b = 25, and C = 20°? 14.32 22.07 23.74 205.18
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to find c side \[\huge\rm c^2 = a^2 +b^2 -2ab \times \cos(c)\] replace by their values and then solve !
12^2+25^2-2(12)(25)xcos?
cos C = ??
20 de
yes right so replace C by 20 de
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Sides: a = 12 b = 25 c = 14.324 (so the first answer is correct) cos c ---> may be cos gamma http://www.triangle-calculator.com/?what=&q=a+%3D+12%2C+b+%3D+25%2C+and+C+%3D+20%C2%B0&submit=Solve
I did get 14.324
though
are you sure ?
yea
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i got different answer
I hope im right
what did you get ?
yes that's not right try again
careful about degree / radian stuff!
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got 205
^ :-)
:-) = that's right
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