the population of humorville is 8,500 people. in this town, jokes travel fast. in one hour, each person who hears a joke tells three other people who have not heard it, and tells no one else. last frieday, a visitor from out of town told the police chief a new joke at 10:00 a.m. how long did it take for everyone in humorville to hear the joke?
@Hero
@amistre64
so, what are your thoughts?
my thoughts is that this is an exponent problem @amistre64
it is an exponent yes have you tried making a list of values? h0 = 1 h1 = 1 + 3 h2 = 1 + 3 + 3(3) h3 = 1 + 3 + 3(3) + 3(3)(3) etc ....
|dw:1429491588506:dw|
no i havent @amistre64
well, making a list helps to see the process
what does my list suggest to you?
This is a geometric sequence which is exponential, but it's more than that. In other words, you need to find after which period, the sum of the sequence reaches 10,000.
to add and multiply @amistre64
doesnt the number of people for a given hour look like a geometric sum? if so, how do we solve a geometric summation?
\[h_n=\sum_{k=0}^{n}3^n\] when does this equate to the entire population?
3^k that is
wait im confused @amistre64
i hope you get more specific than that
i dont understand how to solve a geometric summation
well, with any luck you have a formula laying about for it
the other method is to simply do something nifty
S = 1 + r + r^2 + r^3 + r^4 + ... + r^n -rS = - r - r^2 - r^3 - r^4 + ... + r^n - r^(n+1) when we add these together, almost everything goes to 0
S = 1 + r + r^2 + r^3 + r^4 + ... + r^n -rS = - r - r^2 - r^3 - r^4 + ... + r^n - r^(n+1) --------------------------------------------- (1-r)S= 1 + 0 + 0 + 0 + 0 + ... + 0 -r^(n+1) out goal is to find S so, divide both sides by 1-r \[S=\frac{1-r^{n+1}}{1-r}\]
so now we have a formula to determine the summation of any nth hour. how do we determine the solution to the problem now?
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