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Mathematics 21 Online
OpenStudy (anonymous):

how to write this seqeunce as a summation financial mathematics

OpenStudy (anonymous):

first year 1 end of first year (1+R) 2nd year (1+r) + (1+i) end of second yr (1+R)^2 + (1+i)(1+R) third year (1+i)(1+r)^2 +(1+i)^2(1+r) + (1+i)^2 end of third yr (1+r)^3 + (1+i)(1+r)^2 + (1+i)^2(1+r) 4th year (1+r)^3 + (1+r)^2(1+i) + (1+r)^(1+i)^2 + (1+i)^3 etc... till the tenth yr

OpenStudy (anonymous):

@Michele_Laino

OpenStudy (anonymous):

hey again i have looked at this and i have seen a pattern, this is the enlarged version of what we did before. however, my thought was wrong

OpenStudy (anonymous):

you can see that at the beginning of each year there is an addition of (1+i)^n-1 to the sequence right?

OpenStudy (michele_laino):

yes!

OpenStudy (anonymous):

now excluding the addition of this (1+i) term for each new year, at the end of each year i can write the summation as: \[\sum_{k=0}^{k=n-1}(1+r)^{n-(k+1)}(1+i)^{k}\]

OpenStudy (anonymous):

first year 1 end of first year (1+R) 2nd year (1+r) end of second yr (1+R)^2 + (1+i)(1+R) third year (1+i)(1+r)^2 +(1+i)^2(1+r) end of third yr (1+r)^3 + (1+i)(1+r)^2 + (1+i)^2(1+r) 4th year (1+r)^3 + (1+r)^2(1+i) + (1+r)^(1+i)^2 etc... till the tenth yr

OpenStudy (anonymous):

see how i have removed the (1+i) term from the start of each new year

OpenStudy (anonymous):

just so the summation can represent all those terms

OpenStudy (anonymous):

but i'm not sure where i'm going with this. it looks interesting but i can't seem to add on that extra term so that everything is hunky dory

OpenStudy (anonymous):

you can see the indices of each pair add up to n-1

OpenStudy (anonymous):

or n

OpenStudy (anonymous):

depending if its the beggining or end of the year

OpenStudy (anonymous):

:/

OpenStudy (michele_laino):

please wait I try to write your summation

OpenStudy (anonymous):

: )

OpenStudy (anonymous):

i guess you can represent 1 as (1+i)^0

OpenStudy (anonymous):

that could be a help

OpenStudy (michele_laino):

I got this expression at the beginning of each year: \[\Large \sum\limits_{k = 0}^{n - 1} {{{\left( {1 + r} \right)}^{n - \left( {k + 1} \right)}}{{\left( {1 + i} \right)}^k}} \]

OpenStudy (anonymous):

yep! thats what i got!

OpenStudy (michele_laino):

please can you write the expression at the end of the fourth year?

OpenStudy (anonymous):

sure

OpenStudy (anonymous):

give me a second

OpenStudy (anonymous):

(1+r)^4 + (1+r)^3(1+i) +(1+r)^2(1+i)^2 + (1+r)(1+i)^3

OpenStudy (anonymous):

can you see the pattern?

OpenStudy (michele_laino):

I got this expression: \[\Large \sum\limits_{k = 0}^{n - 1} {{{\left( {1 + r} \right)}^{n - k}}{{\left( {1 + i} \right)}^k}} \]

OpenStudy (anonymous):

is this for everything?

OpenStudy (michele_laino):

that expression is at the end of each year

OpenStudy (anonymous):

let me check

OpenStudy (anonymous):

yep! thats good by me

OpenStudy (anonymous):

would u just use both summations and don't worry about combining?

OpenStudy (michele_laino):

yes! I think so!

OpenStudy (anonymous):

so all you have to do is be careful which summation you are using?

OpenStudy (michele_laino):

that's right!

OpenStudy (anonymous):

ah you've clarified it for me so easily! cheers again!

OpenStudy (michele_laino):

thanks! :):)

OpenStudy (dan815):

buuddyyy!!

OpenStudy (dan815):

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