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What volume would 3.01•1023 molecules of oxygen gas occupy at STP?
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You can solve this question by combining the following two equations: PV=nRT n=n(molecules)/N(A) Where P is the pressure, V is the volume, n is the moles, R is the gas constant, T is the temperature, n(molecules) is the number of molecules, and N(A) is Avogadro's number. Plug in all the values (you should know what P and T are for STP) and solve for V to find your answer!
At STP, one mole of any gas occupies 22.4L. Therefore, find the moles of oxygen first, then multiply it by 22.4L
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