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When a mixture of PH3, P2, and H2 comes to equilibrium at 873 K according to the reaction 2PH3(g)←−→P2(g)+3H2(g)Kp = 398 at 873 K, where Pp2 = 0.418atm and PH2 = 0.829atm .
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what's the question? I'd guess you're looking for the equilibrium pressure of the \(PH_3\), but just plug the pressures into the \(K_P\) equation and solve
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