Question

You want to make five-letter codes that use the letters A, F, E, R, and M without repeating any letter. What is the probability that a randomly chosen code starts with M and ends with E?

0.01

0.02

0.05

0.10

Answer 1

what do you think

Answer 2

i think it is 0.10

Answer 3

hmmm, let me think

Answer 4

How many different letters can you randomly pick for the first letter?

Answer 5

okay so 5 letters and two you pick out so,

Answer 6

i think it is 0.05 chance

Answer 7

think you pinklion23

Answer 8

@pinklion23 2/5 = 0.4

Answer 9

and where so you see 0.4?

Answer 10

i'm just saying your method does not explain anything.

Answer 11

oh *brainfart* :/ well what re you suggesting >o<

Answer 12

Since the letters for the code are picked between 5 different letters (A,F,E,R,M) and letters can't repeat.

The chance of the first letter being M is 1/5 (or 0.2) because there's 5 letters to pick from, and M is only 1 of those 5.

For the second letter, there's 4 available options (A,F,E,R), and we only want E. So the chance would be 1 out of 4 (0.25)

Multiply 0.25 by 0.2 and then you'll you the answer. (Which is indeed 0.05, but I guess in your case it's just a lucky shot).