Question

(z-2) times (z-4)

Answer 1

do you know what the value of z is?

Answer 2

no

Answer 3

@NMVA

Answer 4

is that the full question?

Answer 5

yes

Answer 6

@NMVA

Answer 7

are u figuring it using line segments?

Answer 8

it's multiplying binomials and minomials
@NMVA

Answer 9

ok hold up lemme werk it out

Answer 10

ok, thanks @NMVA

Answer 11

k first of all sorry for taking FOREVER i had to help with my brother

Answer 12

and would it be something like this:
z(to the second power) - 6z + 8?

Answer 13

Yes.

\[(z-2)(z-4)\]
Distribute \((z-2)\) and you have \[z(z-2)-4(z-2)\]
Distribute again:\[z^2-2z-4z+8 = \boxed{z^2-6z+8}\]