Question

For the reaction shown, calculate how many grams of oxygen form when each quantity of reactant completely reacts.
2 KClO3(s) → 2 KCl(s) + 3 O2(g)
a. 2.72 g KClO3
b. 0.361 g KClO3
c. 83.6 kg KClO3
d. 22.5 mg KClO3

maybe im not doing the significant figures correctly(3 sig fig), but I cant figure out what im doing wrong.

Answer 1

Go from grams of reactant to moles of react using molar mass, from the periodic table

Then moles of reactant to moles of product using stoichiometric ratio (the coefficients)

Then from moles of product to grams of product using molar mass.

Make sense?