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Mathematics 16 Online
OpenStudy (anonymous):

The vertices of square HIJK have coordinates H(−3, 2), I(−5, 2), J(−5, 4), and K(−3, 4). Square HIJK was transformed to produce square HꞌIꞌJꞌKꞌ, with coordinates Hꞌ(−3, −2), Iꞌ(−5, −2), and Kꞌ(−3, −4). What are the coordinates of vertex Jꞌ? ( , ) Will give fan and medal

OpenStudy (anonymous):

@dan815

OpenStudy (anonymous):

@sammixboo

OpenStudy (anonymous):

@lordhelix8th

OpenStudy (anonymous):

@iGreen

OpenStudy (anonymous):

@matt101

OpenStudy (anonymous):

@welshfella do u get it

OpenStudy (welshfella):

note that the x coordinate of H and its image H' are the same but the y coordinate of H is 2 and y coordinate of H' is -2.

OpenStudy (welshfella):

this means its a reflection in the x-axis

OpenStudy (anonymous):

ok but the coordinates will be

OpenStudy (anonymous):

sorry i dont understand what it says

OpenStudy (welshfella):

the top x is the position of H and bottom x is the position of H'

OpenStudy (anonymous):

so the coordinate is 2 -3

OpenStudy (welshfella):

its a similar story for the points I , I' , K and K' so for J' the x coordinate will be the same and Y coordinate will be negative of y coordinate of point J

OpenStudy (welshfella):

No - look at coordinates of point J

OpenStudy (anonymous):

-5 4

OpenStudy (welshfella):

actually i messed up the diagram the point should left of y axis...

OpenStudy (anonymous):

ok

OpenStudy (welshfella):

it doesn't matter the answer will still be the same J = (-5,4) so J' = (-5, ?)

OpenStudy (anonymous):

-4

OpenStudy (welshfella):

right J' = (-5,-4)

OpenStudy (anonymous):

thats the answer

OpenStudy (welshfella):

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