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Mathematics 9 Online
OpenStudy (howard-wolowitz):

Can someone help me with this problem:

OpenStudy (mahmood786123):

The picture is to tiny to see

OpenStudy (howard-wolowitz):

click to zoom

OpenStudy (mahmood786123):

OK

OpenStudy (mahmood786123):

I have no idea sorry havent learned this as yet

OpenStudy (michele_laino):

here we can solve the third equation for x, and we get: x=-10-2z is it ok?

OpenStudy (howard-wolowitz):

yes ok

OpenStudy (michele_laino):

now, please you have to substitute that value of x into the first equation, namely: \[ - ( - 10 - 2z) - y - z = 2\] and then you have to solve for y, what do you get?

OpenStudy (howard-wolowitz):

y=z+8

OpenStudy (anonymous):

can i tag u for math please

OpenStudy (michele_laino):

ok! now we have to substitute y=z+8, and x=-10-2z into the second equation, so we get: \[ - \left( { - 10 - 2z} \right) - 3\left( {8 + z} \right) - 2z = 4\] then you have solve that equation for z, what do you get?

OpenStudy (michele_laino):

@Howard-Wolowitz

OpenStudy (howard-wolowitz):

yes

OpenStudy (howard-wolowitz):

srry im lagging

OpenStudy (howard-wolowitz):

z=-6

OpenStudy (michele_laino):

that's right! now you have to substitute z=-6, into the expression for x, and y, namely: x=-10-2*(-6)=...? y=8+(-6)=...?

OpenStudy (howard-wolowitz):

y=2

OpenStudy (michele_laino):

and x?

OpenStudy (michele_laino):

x=-10+12=...?

OpenStudy (michele_laino):

we have: x=2 so the solution of your system is: x=2, y=2, and z=-6 namely the third option

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