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OpenStudy (mahmood786123):
The picture is to tiny to see
OpenStudy (howard-wolowitz):
click to zoom
OpenStudy (mahmood786123):
OK
OpenStudy (mahmood786123):
I have no idea sorry havent learned this as yet
OpenStudy (michele_laino):
here we can solve the third equation for x, and we get:
x=-10-2z
is it ok?
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OpenStudy (howard-wolowitz):
yes ok
OpenStudy (michele_laino):
now, please you have to substitute that value of x into the first equation, namely:
\[ - ( - 10 - 2z) - y - z = 2\]
and then you have to solve for y, what do you get?
OpenStudy (howard-wolowitz):
y=z+8
OpenStudy (anonymous):
can i tag u for math please
OpenStudy (michele_laino):
ok!
now we have to substitute y=z+8, and x=-10-2z into the second equation, so we get:
\[ - \left( { - 10 - 2z} \right) - 3\left( {8 + z} \right) - 2z = 4\]
then you have solve that equation for z, what do you get?
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OpenStudy (michele_laino):
@Howard-Wolowitz
OpenStudy (howard-wolowitz):
yes
OpenStudy (howard-wolowitz):
srry im lagging
OpenStudy (howard-wolowitz):
z=-6
OpenStudy (michele_laino):
that's right!
now you have to substitute z=-6, into the expression for x, and y, namely:
x=-10-2*(-6)=...?
y=8+(-6)=...?
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OpenStudy (howard-wolowitz):
y=2
OpenStudy (michele_laino):
and x?
OpenStudy (michele_laino):
x=-10+12=...?
OpenStudy (michele_laino):
we have:
x=2
so the solution of your system is:
x=2, y=2, and z=-6
namely the third option