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if a line crosses the y -axis at (0,-3) and has a slope of 3 , what is the equation of the line
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y=mx+b m=slope b=y-intercept
so knowing that ^ what do you think the equation of the line is
\(\bf \begin{array}{lllll} &x_1&y_1\\ % (a,b) &({\color{red}{ 0}}\quad ,&{\color{blue}{ -3}})\quad \end{array} \\\quad \\ % slope = m slope = {\color{green}{ m}}= 3 \\ \quad \\ % point-slope intercept y-{\color{blue}{ y_1}}={\color{green}{ m}}(x-{\color{red}{ x_1}})\qquad \textit{plug in the values and solve for "y"}\\ \qquad \uparrow\\ \textit{point-slope form}\)
well... if you're not asked for the slope-intercept form you don't have to solve for "y" then just use the point-slope form
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