Question

The Ka for HCN is 6.2 x 10^-10 Calculate:
a) [H3O+]
b) the pH and the % dissociation for a 0.50 mol/L HCN solution

Answer 1

@peekaboopork i think the concentration of HCN is given in question !
because for (a) part :-
\[\huge \bf [H_3O^{+}]=\sqrt{K_a \times C}\]
where,
\[\large \bf c=concentration~of~molecule\]

Answer 2

Yes. From there, you can find pH by using \(-log[H_3O^+]\).

The \(\%~dissociation=\large \frac{[H^+]}{[HCN]}\)