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Mathematics 21 Online
OpenStudy (help_people):

Help Please?

OpenStudy (help_people):

The table shows data for a class's mid-term and final exams: Mid-Term Final 98 99 98 93 93 93 90 93 88 88 82 86 78 80 75 78 75 78 70 78 68 72 Which data set has the largest standard deviation? Mid-term exams Final exams They have the same standard deviation. There is not enough information.

rvc (rvc):

how can we help you?

OpenStudy (help_people):

@rvc

OpenStudy (anonymous):

do you know how to do standard deviantion?

OpenStudy (help_people):

@BugzytheGreat

OpenStudy (anonymous):

We'd need to find the mean, am I right?

OpenStudy (anonymous):

Step 1. Work out the mean. In the formula above μ (the greek letter "mu") is the mean of all our values ... ... Step 2. Then for each number: subtract the Mean and square the result. ... Step 3. Then work out the mean of those squared differences. ... Step 4. Take the square root of that:

OpenStudy (help_people):

ok

OpenStudy (help_people):

may you guys help me w. all of that ?

OpenStudy (anonymous):

sure so start off by finding the mean of both the midterm and final

rvc (rvc):

yep

OpenStudy (anonymous):

Finding the mean is easy. take all the numbers, add them up, and then divide them by the amount of numbers there are.

OpenStudy (help_people):

ok hold on

OpenStudy (help_people):

83.1818 so so on

OpenStudy (help_people):

guys?

OpenStudy (anonymous):

whats the mean for the finals

rvc (rvc):

r u sure that the mean for mid-term is 83.1818

OpenStudy (anonymous):

yes it is

OpenStudy (help_people):

ok so what next> i am kind of on a time limit and i have a lot oof questions so ....

OpenStudy (help_people):

can we kind of hurry this up?

OpenStudy (anonymous):

whats the mean for the finals

OpenStudy (anonymous):

its 85.27

OpenStudy (help_people):

ok

OpenStudy (anonymous):

now subtract 83 from all the mid term grades and 85 from all the final grades

OpenStudy (help_people):

the answer is b right @rvc @jprose

OpenStudy (anonymous):

yes

rvc (rvc):

yep \(\huge\color{red}{\checkmark}\) All the best :)

OpenStudy (help_people):

would you mind helping me w. another

OpenStudy (anonymous):

sure

OpenStudy (help_people):

The box plots show attendance at a local movie theater and high school basketball games: two bar graphs shown. The top one is labeled Movies. Minimum at 130, Q1 at 162, median at 185, Q3 at 195, maximum at 290. The bottom bar graph is labeled Basketball games. Minimum at 85, Q1 at 170, median at 200, Q3 at 225, maximum at 230. Which of the following best describes how to measure the spread of the data? The IQR is a better measure of spread for movies than it is for basketball games. The standard deviation is a better measure of spread for movies than it is for basketball games. The IQR is the best measurement of spread for games and movies. The standard deviation is the best measurement of spread for games and movies.

OpenStudy (help_people):

OpenStudy (anonymous):

what do you think it is

OpenStudy (help_people):

d? @rvc @jprose

OpenStudy (anonymous):

thats right i think

rvc (rvc):

im not so sure :(

rvc (rvc):

i think @jprose is correct

OpenStudy (help_people):

no its not i got it wrong my first time so thats not right

OpenStudy (help_people):

i have to go but i will be back at 12:47 see ya then thanks

OpenStudy (help_people):

@jprose @rvc

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