Question

What is the equation of the line that is perpendicular to -x + y = 7 and passes through (-1, -1)?


-x + y = 2
-x – y = 2
x – y = 2
-x – y = 0
x + y = 0

Answer 1

if we wite it in slope-intercept form we can find its slope
-x + y = 7
y = x + 7

so slope is 1 ( the coefficient of x)

the slope of the line perpendicular to this line = -1/1 = -1

Answer 2

ok soo option 2?

Answer 3

to find our line we can use the standard form
y - y1 = m(x - x1)

where m = slospe and (x1,y1) is a point on the line

so using the values given

y - (-1) = -1(x - (-1))
y + 1 = -(x + 1)
y + 1 = -x - 1

Answer 4

i am confused..

Answer 5

which part cant you follow?

Answer 6

is the answer A?

Answer 7

no
can you rearrange the last line so as to have the x and y on one side and a number on the other?

Answer 8

y + 1 = -x -1
y + x + 1 = -1
can you continue?

Answer 9

I Think i have it

Answer 10

which one do u think it is?