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Chemistry 13 Online
OpenStudy (anonymous):

How many grams of KOH are present in 32.0 mL of a 5.33 M KOH solution?

OpenStudy (aaronq):

find the moles and convert to grams

OpenStudy (anonymous):

Would that involve finding molarity?

OpenStudy (aaronq):

you've been given the molarity, 5.33 M

OpenStudy (anonymous):

So would you multiply the molarity by milliliters?

OpenStudy (aaronq):

Multiply the molarity by the volume, which needs to be in liters because the units of molarity are mol/L.

OpenStudy (anonymous):

So 5.53/.032

OpenStudy (anonymous):

Sorry 5.53 * .032

OpenStudy (aaronq):

yep that's the moles, now convert to mass

OpenStudy (anonymous):

Thanks for the help

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