Question

use the binomial expression (p+q)^n to calculate a binomial distribution with n=5 and p=0.3. Please just post the steps in a simple, understandable way

Answer 1

For a binomial distribution with parameters n = 5 , p = 0.3 . Find the probabilities of getting : (i) Atleast 3 successes. (ii) Atmost 3 successes. n = 5 , p = 0.3

Answer 2

I don't understand this at all... can you just list the steps with an explanation of each one. I usually get it better when I see all the steps together

Answer 3

it looks like they asked their question in yours ....

Answer 4

what do you understand about expanding a binomial?

Answer 5

there is a long version, and a short version ... well, shorter at least. the formula for the expansion is much simpler to process than all of the distributing.

Answer 6

p+q = 1 is something you need to know, since the sum of all probabilities is 1

(1)^n = 1 for all n, therefore (p+q)^n = 1 only if p+q = 1

Answer 7

the formula for the expansion requires you to know factorials, combinatorics

Answer 8

\[(p+q)^n=\sum_{k=0}^{n}\binom{n}{k}p^kq^{n-k}\]
now the probability of x=k is defined by the kth term of the expansion
\[P(x=k)=\binom{n}{k}p^{k}q^{n-k}\]