Question

find the...

Answer 1

The what?

Answer 2

\[\lim_{x \rightarrow 0}(\sqrt{6+x}-\sqrt{6})/x\]

Answer 3

oh dang what grade is this?

Answer 4

pre-calc / calc

Answer 5

Multiply by the conjugate.

Answer 6

most take it as a junior or senior i think

Answer 7

..............im in 8th grade..this looks like collage hahaha

Answer 8

yeah i know to multiply by the conjugate but i'm having trouble simplifying it

Answer 9

Sure, show me where you're having trouble and we can fix it.

Answer 10

I'm taking precal as a sophomore...

Answer 11

That's not how it works @sleepyjess

Answer 12

oh, whoops, that's what I was taught

Answer 13

\[(6+x-6)/(x \sqrt{6+x}+x \sqrt{6})\]

Answer 14

i think that's how its supposed to go

Answer 15

\[\lim_{x \rightarrow 0} \frac{ (\sqrt{6+x}-6) }{ x } \implies \lim_{x \rightarrow 0} \frac{ \left( \sqrt{6+x}-6 \right) }{ x } \times \frac{ \sqrt{6+x}+6 }{ \sqrt{6+x}+6 }\] right?

Answer 16

square root of 6 too on the top

Answer 17

Ah ok, yeah that looks good

Answer 18

So what can we do with the numerator :P

Answer 19

@sleepyjess are we bragging now? lololol jkjk

Answer 20

well i suppose the 6's cancel

Answer 21

so \[1/(\sqrt{6+x}+\sqrt{x})\]
?

Answer 22

*\[\sqrt{6}\]

Answer 23

You still have x up there

Answer 24

So we cancel it out

Answer 25

Oh wait I see you did that!

Answer 26

Looks good :)

Answer 27

so i would leave it like that?

Answer 28

Yeah you can take the limit now

Answer 29

x->0

Answer 30

\[1/(2\sqrt{6})\]
?

Answer 31

Looks good

Answer 32

alright thanks :)

Answer 33

Np!