A solution is made by dissolving 10.20 grams of glucose (C6H12O6) in 355 grams of water. What is the freezing-point depression of the solvent if the freezing point constant is -1.86 °C/m? Show all of the work needed to solve this problem.

Question

joannablackwelder · Answer

The first step is to find the "m" or molality (moles of solute/kg of solvent)

joannablackwelder · Answer

Then multiply the molality by the freezing point constant to get the change in temp.