A bag contains 3 red, 5 yellow, and 8 blue marbles. How many ways can 2 red, 1 yellow, and 2 blue marbles be chosen?

Question

anonymous · Answer

@amistre64 Can you help me please? I would really, really appreciate it.

amistre64 · Answer

3 choose 2, 5 choose 1, 8 choose 2

and we are choosing 5 out of 16 total ...

seems like multipication tome

amistre64 · Answer

$$\binom{3}{2}\binom{5}{1}\binom{8}{2}$$
the 16 choose 5 is prolly not applicable

amistre64 · Answer

for example:  spose we have 3 males and 3 females

how many ways can we pick 2 male and 1 female? if order doenst matter?

m1 m2 f1
m1 m2 f2
m1 m2 f3

m1 m3 f1
m1 m3 f2
m1 m3 f3

m2 m3 f1
m2 m3 f2
m2 m3 f3

9 ways

3 choose 2,  3 choose 1
        3       *        3           = 9

amistre64 · Answer

IF order of selection matters, it easy to see in the example that each group has 3! ways to order it.  9*5 = 54 ordered ways, but i dint think thats what your question is asking for

anonymous · Answer

I'm sorry, I'm still really confused...

anonymous · Answer

Never mind, I just figured it out! Thanks :)