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Mathematics 13 Online
OpenStudy (anonymous):

Inflection points of x^4-18x^2+4?

OpenStudy (anonymous):

the second derivative is a quadratic, should be easy to find the zeros right?

OpenStudy (anonymous):

My work so far 4x^3-18x^2+4 is the first derivative

OpenStudy (anonymous):

oops

OpenStudy (anonymous):

Wait sorry

OpenStudy (anonymous):

the first derivative does not mean the derivative of the first term!!

OpenStudy (anonymous):

4x^3-36x, I don't know what i was putting down.

OpenStudy (anonymous):

and I didn't mean the first derivative literally.

OpenStudy (anonymous):

12x^2-36

OpenStudy (anonymous):

i know i was just fooling

OpenStudy (anonymous):

being the double derivative.

OpenStudy (anonymous):

12(x^2-3)

OpenStudy (anonymous):

looking good so far

OpenStudy (anonymous):

so you get the zeros right away in your head right?

OpenStudy (anonymous):

No...

OpenStudy (anonymous):

\[x^2-3=0\\ x^2=3\\ x=\pm\sqrt3\] yes

OpenStudy (anonymous):

Oh duh, sorry, it's late.

OpenStudy (anonymous):

lol yeah in your head right? take a break have a beer soda whatever

OpenStudy (anonymous):

Gin and tonic would be prime.

OpenStudy (anonymous):

mmm gin

OpenStudy (anonymous):

The critical points are -3,3, and 0 right? -3 and 0 being the max and 3 being the min?

OpenStudy (anonymous):

Wait -3 is a min.

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