Mathematics
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OpenStudy (anonymous):
Inflection points of x^4-18x^2+4?
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OpenStudy (anonymous):
the second derivative is a quadratic, should be easy to find the zeros right?
OpenStudy (anonymous):
My work so far 4x^3-18x^2+4 is the first derivative
OpenStudy (anonymous):
oops
OpenStudy (anonymous):
Wait sorry
OpenStudy (anonymous):
the first derivative does not mean the derivative of the first term!!
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OpenStudy (anonymous):
4x^3-36x, I don't know what i was putting down.
OpenStudy (anonymous):
and I didn't mean the first derivative literally.
OpenStudy (anonymous):
12x^2-36
OpenStudy (anonymous):
i know i was just fooling
OpenStudy (anonymous):
being the double derivative.
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OpenStudy (anonymous):
12(x^2-3)
OpenStudy (anonymous):
looking good so far
OpenStudy (anonymous):
so you get the zeros right away in your head right?
OpenStudy (anonymous):
No...
OpenStudy (anonymous):
\[x^2-3=0\\
x^2=3\\
x=\pm\sqrt3\] yes
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OpenStudy (anonymous):
Oh duh, sorry, it's late.
OpenStudy (anonymous):
lol yeah in your head right?
take a break
have a beer
soda
whatever
OpenStudy (anonymous):
Gin and tonic would be prime.
OpenStudy (anonymous):
mmm gin
OpenStudy (anonymous):
The critical points are -3,3, and 0 right? -3 and 0 being the max and 3 being the min?
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OpenStudy (anonymous):
Wait -3 is a min.