solve the exponential equation express the solution set in terms of natural logarithms 2^x+8=3
\[2^{x+8}=3\]
Well, you should apply the natural logarithm to both sides.
hint: \[\ln a^x = x \ln a\]
still need more steps to figure it out
\[\ln 2^{x+8} = \ln 3\]
Can you continue?
no sorry still lost
Okay, you know that the logarithm of a power makes the power cones down? so the x+8 will come down in front of the ln2\[(x+8) \ln2 = \ln 3\]
yes ok I remember that
Can you solve for x?
do I distribute ln 2 to x+8
Nope, that would be a little tedious. Divide both sides by ln 2.
...natural log? why not log to base 2 \[2^{x+8}=3\\ \log_2(2^{x+8})=\log_2(3)\\ (x+8)\log_2(2)=\log_2(3)\\ x+8=\log_2(3)\\ x = ... \]
@UnkleRhaukus Because the question requires the answer to be in terms of the `natural log`. So using log base 2 would require a change of base later on, seems tedious.
hmm, you are right, it is important to read the question properly,
@UnkleRhaukus I would have used base 2.
have to go I will workm on this later today
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