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Mathematics 21 Online
OpenStudy (anonymous):

Cartesian expression to polar equation. Correct?

OpenStudy (anonymous):

Polar curve, given: \(\Large r=8\sin\theta\) I multiply times r on both sides, \(\Large r^2=8r\sin\theta\) we know that in general \(\Large r^2=y^2+x^2\) and \(\Large y=r\sin\theta\) So, in this case we have: \(\Large r^2=8r\sin\theta~~~~\Longrightarrow~~~~\Large y^2+x^2=8y\)

OpenStudy (irishboy123):

\[r = 8 \sin \theta\]\[r^2 = 8 r \sin \theta\]\[x^2 + y^2 = 8y\]\[x^2 + y^2 - 8y = 0\]\[x^2 + (y - 4)^2 - 16 = 0\]\[x^2 + (y - 4)^2 = 4^2\]

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