Identify the factors of x^2 + 36y^2. Prime (x + 6y)(x - 6y) (x + 6y)(x + 6y) (x - 6y)(x - 6y)
I think it's A, but im not sure :(
I feel like it could be B to.. because can't you factor 36 by 6?
Any ideas anyone?:L
\[(x-6 i y) (x+6 i y)=x^2+36 y^2 \]
So B? @robtobey
Your answer choices are all wrong. Along with the question itself.
That's what my homework gave me tho? .-.
I'm pretty sure its B because of the formula you have to use.. a^2 - b^2 = (a + b)(a- b)
\[x^2+36y^2 \implies (x)^2+(6y)^2\implies ?\]x and 36y\(^2\) are perfect squares. You just need to find their base.
b. is \[x^2+12 x y+36 y^2 \]
So if none of the answering are up there it's prime?
In the sense that it cannot be factored to give real numbers, yes.
Thank you! @robtobey :)
Your welcome and thank you for the medal.
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