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OpenStudy (anonymous):
Identify the factors of x^2 + 36y^2.
Prime
(x + 6y)(x - 6y)
(x + 6y)(x + 6y)
(x - 6y)(x - 6y)
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OpenStudy (anonymous):
I think it's A, but im not sure :(
OpenStudy (anonymous):
I feel like it could be B to.. because can't you factor 36 by 6?
OpenStudy (anonymous):
Any ideas anyone?:L
OpenStudy (anonymous):
\[(x-6 i y) (x+6 i y)=x^2+36 y^2 \]
OpenStudy (anonymous):
So B? @robtobey
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OpenStudy (jhannybean):
Your answer choices are all wrong. Along with the question itself.
OpenStudy (anonymous):
That's what my homework gave me tho? .-.
OpenStudy (anonymous):
I'm pretty sure its B because of the formula you have to use.. a^2 - b^2 = (a + b)(a- b)
OpenStudy (jhannybean):
\[x^2+36y^2 \implies (x)^2+(6y)^2\implies ?\]x and 36y\(^2\) are perfect squares. You just need to find their base.
OpenStudy (anonymous):
b. is \[x^2+12 x y+36 y^2 \]
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OpenStudy (anonymous):
So if none of the answering are up there it's prime?
OpenStudy (anonymous):
In the sense that it cannot be factored to give real numbers, yes.
OpenStudy (anonymous):
Thank you! @robtobey :)
OpenStudy (anonymous):
Your welcome and thank you for the medal.
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