David kicks a soccer ball off the ground and in the air, with an initial velocity of 35 feet per second. Using the formula H(t) = -16t2 + vt + s, what is the maximum height the soccer ball reaches?
17.9 feet
18.2 feet
18.7 feet
19.1 feet
@amistre64 @triciaal @confluxepic
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OpenStudy (welshfella):
i dont think there's enough information given to answer this question
OpenStudy (anonymous):
well thats all the info i got.
OpenStudy (welshfella):
we dont know the time t , we know v and as the ball is on the ground we can take s to be 0
OpenStudy (anonymous):
okay.
OpenStudy (welshfella):
so we have
h(t) = -16t^2 + 35t
- 2 unknowns
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OpenStudy (anonymous):
okay.
OpenStudy (welshfella):
oh if we differentiate we get
d h / dt = -32t + 35
and this = 0 for maximum h
so t = 35/32 seconds
and this gives h as - 16 * (35/32)^2 + 35 * 35/32
OpenStudy (anonymous):
okay but im confused what do i do?
OpenStudy (welshfella):
hold on - have you done any calculus Finding derivatives?
OpenStudy (anonymous):
no
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OpenStudy (welshfella):
oh ok
OpenStudy (welshfella):
well you can't do it that way then
OpenStudy (anonymous):
ohh
OpenStudy (welshfella):
we need to find the vertex of the graph -=16t^2 + 35t
the graph looks something like this
OpenStudy (anonymous):
i can graph it
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